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Watch the fifth element open load
Watch the fifth element open load






watch the fifth element open load

Thus, it also occurs when accessing tuple indices that do not exist: s = ('Alice', 'Bob')Īgain, start counting with index 0 to get rid of this: s = ('Alice', 'Bob') In fact, the Inde圎rror can occur for all ordered collections where you can use indexing to retrieve certain elements. # n Tuple Inde圎rror: List Index Out of Range To fix the error for strings, make sure that the index falls between the range 0. Genius! Here’s what it looks like on my machine: The error can occur when accessing strings as well. String Inde圎rror: List Index Out of Range Only non-zero elements are included in the list. You can fix this with a simple list comprehension statement that accomplishes the same thing: l =

watch the fifth element open load

The source is simply that the list.pop() method removes the element with value 0.Īll subsequent elements now have a smaller index.īut you iterate over all indices up to len(l)-1 = 6-1 = 5 and the index 5 does not exist in the list after removing elements in a previous iteration. This code snippet is from a StackOverflow question. The Inde圎rror also frequently occurs if you iterate over a list but you remove elemen t s as you iterate over the list: l = Inde圎rror When Modifying a List as You Iterate Over It Eliminate the source of the faulty index.Figure out the faulty index just before the error is thrown.But the general debugging strategy remains even for advanced code projects: Note that this is a minimal example and it doesn’t make a lot of sense. The correct code is, therefore: # CORRECT CODE The final one is the index i=4 which points to the fifth element in the list (remember zero-based indexing: Python starts indexing at index 0!).īut the list has only four elements, so you need to reduce the number of indices you’re iterating over. You can now see all indices used to retrieve an element. The result of this code snippet is still an error.įile "C:\Users\xcent\Desktop\code.py", line 6, in So, let’s insert a print statement before that line: lst = The error message tells you that the error appears in line 5. # File "C:\Users\xcent\Desktop\code.py", line 5, in

watch the fifth element open load

Here’s an example of wrong code that will cause the error to appear: # WRONG CODE This way, you’ll have your wrong index in the shell right before the error message. To achieve this, you can print the index that causes the error before you use it on the list. To pin down the exact problem, check the value of the index just before the error occurs. So, how can you fix the code? Python tells you in which line and on which list the error occurs. Tuple Inde圎rror: List Index Out of Range.String Inde圎rror: List Index Out of Range.Inde圎rror When Modifying a List as You Iterate Over It.How to Fix the Inde圎rror in a For Loop?.








Watch the fifth element open load